Question

5. Find the 95% confidence interval for starting salaries of all US college graduates with masters degree. The sample of 33
7. In 2010 the mean household expenditure for energy was $1450. An economist wants to test if that amount went up in the year
0 0
Add a comment Improve this question Transcribed image text
Answer #1

my dear student as per HOMEWORKLIB RULES I have solved the first one. Thank you.

Add a comment
Know the answer?
Add Answer to:
5. Find the 95% confidence interval for starting salaries of all US college graduates with master's...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 7. In 2010 the mean household expenditure for energy was $1450. An economist wants to test...

    7. In 2010 the mean household expenditure for energy was $1450. An economist wants to test if that amount went up in the year 2014. He used a sample of 45 households and found the mean expenditure for energy in that sample to be $1570, and the standard deviation in that sample to be $415. Is there sufficient evidence to support his claim that the expenditure for energy went up, if we use the a=0.05 level of significance? Fill in...

  • In order to find the 95% confidence interval of the true mean, how large of a...

    In order to find the 95% confidence interval of the true mean, how large of a sample size would be necessary to be accurate within 0.1 g. given a standard deviation of 0.3 g? (8 points) 9 10, A T V network claims that 20% of the viewing public watches a certain one of its shows. A survey of 100 TV viewers found that 13 watch the show. If a 0.05, is there enough evidence to reject the network's claim?...

  • Question 2 ases 5 pts Je Use the confidence level and sample data to find a...

    Question 2 ases 5 pts Je Use the confidence level and sample data to find a confidence interval for estimating the population u. Find the margin of error E and round your answer to the nearest tenth. n 49, = 87,5 - 12: 90% confidence Question 4 5 pts Use the confidence level and sample data to find a confidence interval for estimating the population p. Round your answer to the nearest tenth, if necessary. Test scores: n - 100...

  • In a random sample of 565 college students, 150 had part-time jobs. Find the margin of...

    In a random sample of 565 college students, 150 had part-time jobs. Find the margin of error for the 92.5 percent confidence interval used to estimate the population proportion SELECT ALL APPLICABLE CHOICES A) B) 0.0321 0.03308 C) None of These Assume that a simple random sample has been selected from a normally distributed population and test the given claim. State the final conclusion that addresses the original claim and select three correct choices. A test of sobriety involves measuring...

  • A. B. C. D. Construct a confidence interval suitable for testing claim that students taking non...

    A. B. C. D. Construct a confidence interval suitable for testing claim that students taking non proctored tests get higher mean score than those taking proctored tests. ___<µ1 - µ2 < ____ Yes/No____ because the confidence interval contains only positive values/only negative values/zero ______. E. Construct a confidence interval suitable for testing claim that students taking non proctored tests get higher mean score than those taking proctored tests. ___<µ1 - µ2 < ____ Yes/No____ because the confidence interval contains only...

  • A. B. The​ 95% confidence interval is _____ <μd< _____. ​(Round to two decimal places as​...

    A. B. The​ 95% confidence interval is _____ <μd< _____. ​(Round to two decimal places as​ needed.) What does the confidence interval suggest about farmer​ Joe's claim that type 1 seed is better than type 2​ seed? A. Because the confidence interval only includes positive values and does not include ​zero, there is not sufficient evidence to support farmer​ Joe's claim. B. Because the confidence interval includes ​zero, there is sufficient evidence to support farmer​ Joe's claim. C. Because the...

  • a. An analyst from an energy research institute in California wishes to estimate the 95% confidence...

    a. An analyst from an energy research institute in California wishes to estimate the 95% confidence interval for the average price of unleaded gasoline in the state. In particular, she does not want the sample mean to deviate from the population mean by more than $0.06. What is the minimum number of gas stations that she should include in her sample if she uses the standard deviation estimate of $0.35, as reported in the popular press? Round intermediate calculations to...

  • Find the indicated critical z value. the value of zan that corresponds to a confidence level...

    Find the indicated critical z value. the value of zan that corresponds to a confidence level of 97 80% Use the given degree of confidence 2) Of 88 selected and sample data to construct a confidence interval for the population proportion p adults selected randomly from one town 69 have health insurance. Find a 90% confidence interval for the true proportion of all adults in the town who have health insurance the given degree of confidence and sample data to...

  • A. Based on the confidence interval, can one reject the claim that when the 13th day...

    A. Based on the confidence interval, can one reject the claim that when the 13th day of the month falls on a Friday, the numbers of hospital admissions from motor vehicle crashes are not affected? A. Yes, because the confidence interval does not include zero. B. No, because the confidence interval includes zero. B. C. D. P.S Can you please answer part A-D. I am very sick and I can't think right now. Please help me im begging you. My...

  • Winter 2018 AT 103 Test II Chapters 6-11 a( \ 1. The average number of miles that 90 truckers drove in a day was 540 with a standard what is the 99% confidence interval of the true mean number of...

    Winter 2018 AT 103 Test II Chapters 6-11 a( \ 1. The average number of miles that 90 truckers drove in a day was 540 with a standard what is the 99% confidence interval of the true mean number of deviation of 40 miles, miles driven by all truckers? Dr. Christina Cuttleman, a nutritionist, claims that the average number ofcalories in a serving of popcorn is 75 with a standard deviation of 7. A sample of 50 servings of popcorn...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT