Question

QUESTION 7 A component undergoes a cyclic loading which results in the following maximum and minimum stresses, 45kpsi and -15

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Here\\\\\sigma_{max}=45\,\,kpsi \,\,\,and\,\,\,\sigma_{min}=-15\,\,kpsi\\\\Now,\,we\,\,know\,\,that\,\,mean\,\,stress\\\\\sigma_m= \frac{\sigma_{max}+\sigma_{min}}{2}\\\\So,\\\\ \sigma_m=\frac{45+(-15)}{2}\\\\ \sigma_m=15\,\,kpsi

So Mean stress is 15 kpsi.

Add a comment
Know the answer?
Add Answer to:
QUESTION 7 A component undergoes a cyclic loading which results in the following maximum and minimum...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A 1045 hot rolled steel rod undergoes axial cyclic loading from a minimum stress of 2...

    A 1045 hot rolled steel rod undergoes axial cyclic loading from a minimum stress of 2 kpsi to a maximum of 10 kpsi. The rod has a hole in the center of bar, with a Kt 1.7, and notch sensitivity factor 0.9. The yield strength of bar is 45 kpsi, ultimate strength 82 kpsi, fully endurance limit of 20 kpsi, fatigue strength fraction 0.85. 1. a. Using modified goodman criteria, find FOS b. lfinfinite life is not predicted estimate the...

  • answer E,F,G and H please 2. A bar of steel undergoes cyclic loading such that max...

    answer E,F,G and H please 2. A bar of steel undergoes cyclic loading such that max = 60 kpsi and Omin = -20 kpsi. For the material, Sut = 80 kpsi, 5y = 65 kpsi,ka = 1.107. ky = 0.858, ke = ka = k, = k, = 1, and f = 0.9. (a) Calculate the alternating stress. (2 points) (b) Calculate the meani median) stress. (2 points) (c) Calculate the fully corrected endurance limit. (6 points) (d) Calculate the...

  • Question 4 It is estimated that a particular aluminium component has been exposed to the following...

    Question 4 It is estimated that a particular aluminium component has been exposed to the following levels of service each year for 5 years An alternating stress range of 150 MPa about a mean stress of 50 MPa for 500,000 cycles and an alternating stress range of 180 MPa about a mean stress of 60 MPa for 200,000 cycles. The aluminium has an ultimate tensile strength Crs = 240MP2. The material follows Basquin's Law for high-cycle fatigue, i.e Δσν,-C where...

  • 12. A M 116*2 SAE grade 8.8 bolt is subject to a cyclic stress. The minimum...

    12. A M 116*2 SAE grade 8.8 bolt is subject to a cyclic stress. The minimum nominal stress in the tensile area is calculated to be 200 Mpa (corresponding to its initial tension with no external load) and maximum nominal stress is 400 Mpa (corresponding to maximum external load). Determine the factor of safety guarding against eventual fatigue failure for this bolt. a. 0.85 b. 1.15 C. 1.65 d. 1.82 e. None of these

  • For the beam and loading shown draw a shear and moment diagram then determine the minimum...

    For the beam and loading shown draw a shear and moment diagram then determine the minimum required width b, knowing that for the grade of timber used, the maximum allowable normal stress is 12 MPa and the maximum allowable shear stress is 822 kPa. The dimensions are the following: a = 148 mm, LAB = 0.9 m, LBC = 1.1 m, LCE = 1.1 m, LED = 0.5 m, and the loading is PB = 2.3 kN, PC = 4.7...

  • 1. Sketch stress distribution in the cross-sections (defined by the dashed-lines) for the following loading cases....

    1. Sketch stress distribution in the cross-sections (defined by the dashed-lines) for the following loading cases. If there are both normal and shear stresses, sketch them separately. Also indicate the subscripts for each stress component you sketch, according to the given coordinate system. a) Uni-axial (2pts) b) Torsion (2pts) (for this case use cylindrical coordinate to determine the subscripts of the shear stress, axial direction x-axis, radial direction r, and circumferential direction e.) C) Transverse loading 1 (3pts) d) Transverse...

  • For the plot shown above, what is the value of the cyclic stress at A? a)...

    For the plot shown above, what is the value of the cyclic stress at A? a) 35ksi b) 40ksi c) 45ksi d)30ksi For the plot of the Soderberg line in Question 5, what is the value of the steady stress B? a) 55 ksi b) 72 ksi c) 35 ksi d)40 ksi Please use the Soderberg line in the previous question to solve this problem. What is the maximum magnitude of an additional steady stress that can be put on...

  • QUESTION 91 Which of these curves have equal minimum wavelength and equal maximum energy? Number of...

    QUESTION 91 Which of these curves have equal minimum wavelength and equal maximum energy? Number of x-rays 25 100 125 50 75 Energy (Kev) a. O A, B, and b. O A and B co A and d. O Band C e. O None of the above

  • The mechanical component shown in the figure is subjected to variable loading conditions that cau...

    The mechanical component shown in the figure is subjected to variable loading conditions that cause the axial stresses to fluctuate as indicated in the stress-time history. The material of the part is AISI 1045 HR steel with an ultimate static strength of 570 MPa. The part has been tested in the laboratory under different completely reversed stress amplitudes, the fatigue life results of these tests are shown in the table a) The S-N diagram of the part based on the...

  • Question 16 Which of the following statements is True? iff has a local maximum or minimum...

    Question 16 Which of the following statements is True? iff has a local maximum or minimum at a point (a,b) and the partial derivatives fly exist then(a,b) - fy(a,b) - 0 A local maximum is always larger than a local minimum A local minimum is always smaller than a local maximum, off has a critical point at (a,b) and / (0,6) - 4,1yyla,b) - 2. /vy(a,b) – 3, then f has a local minimum at (a,b) none of the given...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT