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Construct an 80% confidence interval for the difference between two population means using the sample data below that have be
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Answer #1

Sample mean for the Sample 1 is, m1 = 409.083 and for the Sample 2 is, m2 = 353.5

The pooled standard deviation is given by Sp = 45.41922

Therefore the confidence interval is given by ( (m1 - m2) - t Sp\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}} , (m1 - m2) + t Sp\sqrt{\frac{1}{n_{1}}+\frac{1}{n_{2}}} )

The value of t for 80% confidence level and degrees of freedom n1 + n2 -2= 22 is t = 1.321

Therefore the confidence interval for the difference between the two population means is given by ( 31.09 ,  80.08 ) (rounded to two decimal points)

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