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Question 4 (5 points) An acetylene welding tank has a gauge pressure of 1880 psi at 40 degrees Fahrenheit. If the tank temper
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Answer #1

answer is option A 2069 psi.

P1 = 1880 psi

T1 = 40 F = 499.67 R

P2 = ?

T2 = 90 F = 549.67 R

so, (P1 / T1) = (P2 / T2)

(1880 x 549.67 / 499.67) = P2

P2 = 2068.12 psi

which is near about P2 = 2069 psi

so option A is correct.

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