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Question 2 Suppose that the genders of the three children of a certain family are soon to be revealed. Outcomes are thus trip
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Answer #1

In all, there are 8 possible outcomes.

We observe that in these outcomes, the possible values that X can take is -4, -8, and -16.

Now, there are 4 outcomes (gbb, bbb, bbg, bgb) that correspond to -4.

P(X = -4) = 4/8 = 1/2

Similarly,

P(X = -8) = 3/8 = 0.375

P(X = -16) = 1/8 = 0.125

X -4 -8 -16
P(X) 0.5 0.375 0.125
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