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An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of heads (h) and tails (o) which we write hth, int,
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Answer #1

COR Total output =8 Number of counts foo X=1 = 6 = P(X=1) = 6 =0 Number of counts foo xe - > X=-3) = Yalue x ofx I Br22 60100

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Answer #2

An ordinary (fair) coin is tossed 3 times. Outcomes are thus triples of "heads" (

h

) and "tails" (

t

)
 which we write 

hth

ttt

etc. For each outcome, let 

R

 be the random variable counting the number of heads in each outcome. For example, if the outcome is 

hht

,
 then 

=Rhht2

.
 Suppose that the random variable 

X

 is defined in terms of 

R

 as follows: 

=XR1

.
 The values of 

X

 are given in the table below.

Outcome

hhh

hth

ttt

thh

hht

tht

tth

htt

Value of 

X

2

1

1

1

1

0

0

0


Calculate the values of the probability distribution function of 

X

, i.e. the function 

pX

.
 First, fill in the first row with the values of 

X

.
 Then fill in the appropriate probabilities in the second row.


answered by: anonymous
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