Question

QUESTION 1 Suppose that an engineer wants to create a three bit adder using the method described in Lecture 25. As part of the design process, the engineer creates the following building block component: a b Cin Full Adder Cout s In order to create the three bit adder, each of the three building blocks will need to be correctly connected together. In the circuit below, each of the possible connection points has been labeled with a number: A[2] 2 3 4 5 6 7 8 9 а b Cin а b Cin a b Cin Full Adder Full Adder Full Adder Cout s Cout s Cout s C2 S2 C1 Si Co So

Answer 1

Please go through the pictures.......

1 Questiont Solution a b Cin F.A cout - Full Addey Adds a bit no's with app CARRY. Cout s So for og but Adden (2 nos) with carry we'll need of full adders & Inputs A[2:0] A[2] A[1] A[0] => 3 bits B[ 20] » B[2] B[i] B [o] 3 bits Adding => [2] C[i]' c[o] Cine A[2] (ACI] Atol 'Cin B[2] B[1] B[o] s [2]' [1], 5[o] final FAZ I FAZI FAL need t So we just give output carry of previous full Adder to input carry of next full Adder A[2] cin (Mlp CARRY) Given in Question (trenerally th S, Co so final given then assumed fi at points a,b of fAs. (Cinzol we'll give our appsa. A[2] All ]A[o] B[2] BLA] B [0] W H 4 억 & C[0] 26 & C[i] > 3 f Cinta 7 89 4 2 3 a b cinl a b cin a b cinl Couts Couts Cout s سا Сі If not » C2 O/P CARRY aan V 5 ny

So it will (the circuit will) just add the A[2:0] & B[2:0] and will agive Olp) Cout SUM C B E А D B[0] C[2] s[2] SCIJ SCO] Now, option Input 2 » B[2] Input 3 = cła Input 4 = A[s Input 5 8 [2] Input 6 > C[o] G Input 7 > A[o] Input 87 Input I 0 (cin) H Answer (1) Questions & Solution Now, in this question it is just like the previous but one but it has one ilp A[2:0 A[2:0] and the and alp will be 8[2:0) = since it is an incrementer A derrice which adds 1 So we've B[2:0]=00 € to the epp. th B[2] BTI) Bło] Already! Now, one more thing here Cin=o is cabready given given. So rest inputs =) 2 (H) O 6 » (D) C[0] 3 (NOT GIVEN) CE] 4 » (A) A[1] 5 = (1.0 It is just like Qui. but Brel=001 Answer (2) O 01 Y y » (G) ACO] 8 » (E). 1 58V B[2]

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