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The temperature of a sample of silver increased by 22.5 °C when 263 J of heat was applied. What is the mass of the sample? Su
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Answer #1

* Heat absorb 95 m с ДТ Specific heat of solve C = 0.2357/96 2637= m X 0.2357 x 22°59 ge 263 - 8:2875 m ma 263 g=49.7399 5-

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