Question

Question Helpo A financial services committee had 60 members, of which 9 were women. If 7 members are selected at random, find the probability that the group of 7 would be composed as the following a. 4 men and 3 women b. 6 men and 1 woman c. at least one woman The probability that the group will consist of 4 men and 3 women is (Round to four decimal places as needed.)

Answer 1

are so from the the gân Hoformation, there members in the committee. In to members, a were women and the remaining 5) were mem. 3 de random from o number o ways in which + members can be Selected at random 60 60! 60! 7!(60-4)! 7.53 GOCA

can be debeded from of ways O number in cohich in men SI 51 cm ① number e coys in which n comen can be Labeled 9 from number in which in men and of coaps can be delected - 51 mx 9C, qCn n women probability that the group of 7 could be "Campobrala o 4 orson and 3 comen and "Combode 'P C4 mars and 3 comen) = number in 4 men of ways & women can be delected umber 9 says in which 7 members can be delected 516 4X 9C, 511 4147!' 3! 6! 601 249900 x 84 7! 537 386206920 0.05435 5.435% 9! X 60 C7

(a) ie PCh men • men and 3 women b) - 0.0544 (b) P(6 men and I comen) 516x9 C, 60 C7 51! 91 6145! 118! х 60! 7! 531 18009460 X 9 386206920 0.4197 (c) plat least one comen) p (women 21) 9C, X51 66 + 9C2516, +90 51C, + 9C x 51C3 +9C551C2 +96510, +9Cq51c. 6067 = 9x 18009460 + 36X 2349060+ 84x249900 f 126x20825 +126X1275 + 84x51+ 36X | 386206920 =270431820 0.7002 386206920
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