A committee of 3 people is selected at random from 4 men and 8 women. What is the probability that the the committee contains both men and women given that the committee is not composed of all men?
number of ways not composed of all men =N(total number of ways)-N(number of ways with all men)
=(12C3)-(4C3)=220-4 =216
number of ways contains both men and women =N(total number of ways)--N(number of ways with all men)--N(number of ways with all women)
=(12C3)-(4C3)-(8C3)=220-4-56 =160
therefore probability that the the committee contains both men and women given that the committee is not composed of all men =160/216 =20/27
A committee of 3 people is selected at random from 4 men and 8 women. What...
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