Question
You have generated three mutants: one has a constitutively active ATM, one has a loss of function of Wee1 and the last has a securin that can no longer be degraded. What do you expect would happen to the percentage of cells in each part of the cell cycle - use the table below and indicate increase, decrease or same when compared to wild-type.

3) You have generated three mutants: one has a constitutively active ATM, one has a loss of function of Wee1 and the last has
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Answer #1

   Effect of mutation of any protein that has role in cell division,is pronounced only in the stage where it has some role and the stage next to that.

ATM helps in recruiting proteins needed for DNA rapair.Because of this cell-cycle gets arrest.So,number of cells in S phase increases,because cell cycle gets arrested at this stage.

Wee1 function is to inhibit cells entry into M phase,if cell is not fit enough to enter.So,loss of function of Wee1 leads to increase in number of cells at M stage and thus decreasing number of cells in G2 phase.

Securin prevents pre-mature entry of cell into anaphase.It allows to enter into anaphase only after they devoloped properly.

So,lose of function by Securin,fastens M phase of cell division.So,number of cells that are present in M PHASE decreases.This inturn increases cells which are at G1 stage(stage just after M phase)

ATM Wee1 Securin
G1 Remains same Remains same Increase
S phase Increase Remains same Remains same
G2 decrease Decrease Remains same
M phase Remains same Increase Decrease
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