Homework Answers
From the given information,
By using confidence interval calculator,
The required 98% confidence interval is given by,
(1.23,4.31)
Hence, Last option is correct.
Please help me out by just rating the answer.
Thank you so much.
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Question 7 2 pts Find the 98% confidence interval for the normally distributed difference between two...
Please Show Work Construct a 98% confidence interval for the difference between two population means using...
Please Show Work
Construct a 98% confidence interval for the difference between two population means using the sample data below that have been selected from normally distributed populations with different population variances. Sample 1 Sample 2 392 425 363 476 403 312 294 307 394 348 354 394 308 280 377 379 331 413 398 464 404 283 435 401 The 98% confidence interval is < (41 - H2)s (Round to two decimal places as needed.)
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions...
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions given the following information from independent samples: Sample 1: proportion p = 0.40. = 93 Sample 2: proportion p2 = 0.50, n2 = 86 O (-0.325,0.015) O 1-0.291,0.091) O (-0.179.-0.021) O (-0.298,-0.002) O (-0.417.0.317)
Use a t-distribution to find a confidence interval for the difference in means ud=u1-u2 using the...
Use a t-distribution to find a confidence interval for the difference in means ud=u1-u2 using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d=x1-x2 . a 95% confidence interval for ud using the paired difference sample results xd-3.4, sd=2.1, nd=30
6. Assume you want to construct a 98% confidence interval with a sample of n-10 from...
6. Assume you want to construct a 98% confidence interval with a sample of n-10 from ofa nomally distributed population. Find the critical value ta2 (1 point) 2764 02.821 0 1.383 O3.250 7. A sample of size n - 12 does not have a known population standard deviation. The population (1 point) appears to be normally distributed. Determine whether a margin of error should be calculated using a critical value of za2, a critical value of t, or neither. a...
Construct a 98% confidence interval for the population standard deviation σ of a random sample of...
Construct a 98% confidence interval for the population standard deviation σ of a random sample of 20 crates which have a mean weight of 154.2 pounds and a standard deviation of 9.4 pounds. Assume the population is normally distributed. The confidence interval is: Group of answer choices between 6.52 and 15.02 between 6.81 and 14.83 between 42.51 and 225.60 between 46.39 and 219.94
Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the...
Use a t-distribution to find a confidence interval for the difference in means μd=μ1-μ2 using the relevant sample results from paired data. Assume the results come from random samples from populations that are approximately normally distributed, and that differences are computed using d=x1-x2 . A 95% confidence interval for μd using the paired difference sample results x¯d=3.1, sd=2.4, nd=30. Give the best estimate for μd, the margin of error, and the confidence interval. Enter the exact answer for the best...
Construct the indicated confidence interval for the difference between the two population means. Assume that the...
Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are independent simple random samples selected from normally distributed populations. Do not assume that the population standard deviations are equal. Independent samples from two different populations yield the following data. x1 = 958, x2 = 157, s1 = 77, s2 = 88. The sample size is 478 for both samples. Find the 85% confidence interval for ?1 - ?2.
Question 14 8 pts Use the given degree of confidence and sample data to find a...
Question 14 8 pts Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation o. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation. College students' annual earnings: 98% confidence; n = 9, sample mean is $4121,s = $873 $531<o< $1708 $590 <o< $1672 $551<o<$1925 $687 <o< $1139
Find the 98% confidence interval for the difference between two means based on this information about...
Find the 98% confidence interval for the difference between two means based on this information about two samples. Assume independent samples from normal populations. (Use conservative degrees of freedom.) (Give your answers correct to two decimal places.) Sample Number Mean Std. Dev. 1 18 40 30 2 17 28 25 Lower : ??? Upper: ???
A 90% confidence interval for the difference between the means of two independent populations with unknown population...
A 90% confidence interval for the difference between the means of two independent populations with unknown population standard deviations is found to be (-0.2, 5.4). Which of the following statements is/are correct? CHECK ALL THAT APPLY. A. A two-sided two-sample t-test testing for a difference between the two population means is not rejected at the 10% significance level. B. The standard error of the difference between the two observed sample means is 2.6. C. A two-sided paired t-test testing for...
Please Show Work
Construct a 98% confidence interval for the difference between two population means using the sample data below that have been selected from normally distributed populations with different population variances. Sample 1 Sample 2 392 425 363 476 403 312 294 307 394 348 354 394 308 280 377 379 331 413 398 464 404 283 435 401 The 98% confidence interval is < (41 - H2)s (Round to two decimal places as needed.)
Question 8 2 pts Find the 99% confidence interval for the difference between two population proportions given the following information from independent samples: Sample 1: proportion p = 0.40. = 93 Sample 2: proportion p2 = 0.50, n2 = 86 O (-0.325,0.015) O 1-0.291,0.091) O (-0.179.-0.021) O (-0.298,-0.002) O (-0.417.0.317)
6. Assume you want to construct a 98% confidence interval with a sample of n-10 from ofa nomally distributed population. Find the critical value ta2 (1 point) 2764 02.821 0 1.383 O3.250 7. A sample of size n - 12 does not have a known population standard deviation. The population (1 point) appears to be normally distributed. Determine whether a margin of error should be calculated using a critical value of za2, a critical value of t, or neither. a...
Question 14 8 pts Use the given degree of confidence and sample data to find a confidence interval for the population standard deviation o. Assume that the population has a normal distribution. Round the confidence interval limits to the same number of decimal places as the sample standard deviation. College students' annual earnings: 98% confidence; n = 9, sample mean is $4121,s = $873 $531<o< $1708 $590 <o< $1672 $551<o<$1925 $687 <o< $1139
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