Construct a 98% confidence interval for the population standard deviation σ of a random sample of 20 crates which have a mean weight of 154.2 pounds and a standard deviation of 9.4 pounds. Assume the population is normally distributed. The confidence interval is: Group of answer choices between 6.52 and 15.02 between 6.81 and 14.83 between 42.51 and 225.60 between 46.39 and 219.94
From chi-square table,
Chi-square critical values at 0.02 significance level with 19 df = 7.633 ,36.191
98% confidence interval for is
sqrt [ (n -1 ) * S2 / U ] < < sqrt [ (n -1 ) * S2 / UL]
sqrt [ (20 - 1) * 9.42 / 36.191 ] < < sqrt [ (20 - 1) * 9.42 / 7.633 ]
6.81 < < 14.83
Between 6.81 and 14.83
Construct a 98% confidence interval for the population standard deviation σ of a random sample of...
Construct a 95% confidence interval for the population standard deviation σ of a random sample of 15 crates which have a mean weight of 165.2 pounds and a standard deviation of 12.9 pounds. Assume the population is normally distributed
Construct a 95% confidence interval for the population standard deviation sigma of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 12.5 pounds. Assume the population is normally distributed.
Construct a 95% confidence interval for the population standard deviation o of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 13.5 pounds. Assume the population is normally distributed.
I. Construct a 95% confidence interval for the population standard deviation sigmaơ of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 10.9 (10.1 or 14.3) pounds. Assume the population is normally distributed.
Show Work a Construct a 95% confidence interval for the population standard deviations of a random sample of 15 crates which have a mean weight of 165 2 pounds and a standard deviation of 11.6 pounds. Round to the nearest thousandth. Assume the population is normally distributed O.A. (8.493,18.294) O B. (8.918,16.932) OC (2.494,5.371) OD. (72.125,334.667) Jick to select your answer. Sample tests and quizzes can be taken for practice or to build your study plan. Sample tests and quizzes...
13. A random sample is drawn from a population of known standard deviation 11.3. Construct a 90% confidence interval for the population mean based on the information given (not all of the information given need be used). a. n-36, x =105.2, s=11.2 b. n-100, x =105.2, s - 11.2 14. A random sample is drawn from a population of unknown standard deviation. Construct a 99%99% confidence interval for the population mean based on the information given. a. n=49, x 17.1,...
Use the given data to construct a confidence interval for the population standard deviation, A SELECT ALL APPLICABLE CHOICES B) Assume that the population has a normal distribution: The football coach randomly selected the following players and timed how long each player took to perform a certain drill. The times (in minutes) were: 4.1048445 < ơ < 9.8431834 2.7048445 < σ < 9.2431834 C) D) None of These 4.1048445 < ơ < 8.0431834 [144, 5, 8,11,15,10] Find a 95.0 confidence...
X6.2.9-TConstruct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed c = 0.90, x̅ = 12.9, s = 4.0, n = 9 The 90% confidence interval using a t-distribution is 6.2.17-T In a random sample of 26 people, the mean commute time to work was 34.8 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ...
Use the standard normal distribution or the t distribution to construct a 9 % confidence interval for the population mean Justify your decision if neither distribution can be used, explain why Interpret the results ln a random sample of 17 mortgage institutions, the mean interest rate was 3.69% and the standard deviation was 36% Assume the iterest rates are normally distributed Which distribution should be used to construct the confidence interval? ○ A. Use a t-distribution because it is a...
Construct a 98% confidence interval to estimate the population mean with x=59 and σ=13 for the following sample sizes. a) n equals= 30 b) n equals= 49 c) n equals= 64 a) With 98% confidence, when n=30,the population mean is between the lower limit of blank and the upper limit of. (Round to two decimal places as needed.)