Construct a 95% confidence interval for the population standard deviation σ of a random sample of 15 crates which have a mean weight of 165.2 pounds and a standard deviation of 12.9 pounds. Assume the population is normally distributed
Construct a 95% confidence interval for the population standard deviation σ of a random sample of...
Construct a 95% confidence interval for the population standard deviation sigma of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 12.5 pounds. Assume the population is normally distributed.
Construct a 95% confidence interval for the population standard deviation o of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 13.5 pounds. Assume the population is normally distributed.
I. Construct a 95% confidence interval for the population standard deviation sigmaơ of a random sample of 15 men who have a mean weight of 165.2 pounds with a standard deviation of 10.9 (10.1 or 14.3) pounds. Assume the population is normally distributed.
Construct a 98% confidence interval for the population standard deviation σ of a random sample of 20 crates which have a mean weight of 154.2 pounds and a standard deviation of 9.4 pounds. Assume the population is normally distributed. The confidence interval is: Group of answer choices between 6.52 and 15.02 between 6.81 and 14.83 between 42.51 and 225.60 between 46.39 and 219.94
Show Work a Construct a 95% confidence interval for the population standard deviations of a random sample of 15 crates which have a mean weight of 165 2 pounds and a standard deviation of 11.6 pounds. Round to the nearest thousandth. Assume the population is normally distributed O.A. (8.493,18.294) O B. (8.918,16.932) OC (2.494,5.371) OD. (72.125,334.667) Jick to select your answer. Sample tests and quizzes can be taken for practice or to build your study plan. Sample tests and quizzes...
The utility bills (in dollars) of 10 randomly selected homeowners in one city are listed below. Construct a 95% confidence interval for the mean. Assume the population is normally distributed. 70, 72, 71, 70, 69, 73, 69, 68, 70, 78 (68.95, 73.05) (69.00, 78.00) (70.05, 72.95) (68.13, 73.87) Suppose a 98% confidence interval for μ turns out to be (1000, 2100). If this interval was based on a sample of size n = 22, find the value of the margin...
Use the standard normal distribution or the t-distribution to construct the indicated confidence interval for the population mean of each data set. Justify your decision. If neither distribution can be used, explain why. Interpret the results. (a) In a random sample of 36 patients, the mean waiting time at a dentist’s office was 24 minutes and the standard deviation was 7.5 minutes. Construct a 90% confidence interval for the population mean. (b) In a random sample of 25 cereal boxes,...
X6.2.9-TConstruct the indicated confidence interval for the population mean μ using the t-distribution. Assume the population is normally distributed c = 0.90, x̅ = 12.9, s = 4.0, n = 9 The 90% confidence interval using a t-distribution is 6.2.17-T In a random sample of 26 people, the mean commute time to work was 34.8 minutes and the standard deviation was 7.2 minutes. Assume the population is normally distributed and use a t-distribution to construct a 98% confidence interval for the population mean μ...
Construct a 95% confidence interval for the mean weight of all new Ford Mustangs if a random sample of 40 of these automobiles had a mean weight of 3,200 pounds. Assume from previous studies that the population standard deviation is 160 pounds. PLEASE SHOW WORK AND CLEARLY THANK YOU MEANING THE CONFIDENCE INTERVAL
A test on a random sample of 50 water balloons yielded a sample average weight of 1.2 pounds. Prior studies have shown that the population standard deviation is 0.2 pounds. Assume that water balloon weight is normally distributed. Construct a 95% confidence interval of the population mean?