Question

A spring on a horizontal surface can be stretched and held 0.7 m from its equilibrium position with a force of 70 N. a. How much work is done in stretching the spring 5.5 m from its equilibrium position? b. How much work is done in compressing the spring 1.5 m from its equilibrium position? a. Set up the integral that gives the work done in stretching the spring 5.5 m from its equilibrium position. Use increasing limits of integration. dx (Type exact answers.) The amount of work done is (Simplify your answer.) b. Set up the integral that gives the work done in compressing the spring 1.5 m from its equilibrium position. Use decreasing limits of integration. dx (Type exact answers.) The amount of work done is

Answer 1

x2 0.im Force =TON F-km K= E= 100 N/m a) Work done in Streeto retching the Spring 5.5m from its equilibrium position is 15.5 ssistan Kada Wa - so 15.5 100 २ = 100 (90,25 -0) = 1512.5 J b) work done be in compressing the spring 1.5m from its equi brium position 1-5 Kada 1.5 100x (0 - 235 2 =-112.5