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answer A and B please
A spring on a horizontal surface can be stretched and held 0.6 m from its equilibrium position with a force of 48 N a. How mu
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Answer #1

By Hookes law, (pod Ezka 48-K (06) pe 480 6 k= @u8 0.6 780 k= 80 W/m 4.5 Bo w = fkx de 45 = 80 a da de We so (rujus = 40[4.5

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