Question

what is the product of the following reaction?

1.) KMnO4 cold dilute 2.) NaOH O OH + IO||III. H H OH OH enantiomer enantiomer A B D

Answer 1

Option A is the correct answer.

Action of cold dil KMnO₄ followed by NaOH on alkene results in the formation of diols and the two OH grous are added on the same side of the double bond. So option A is the correct one where both the OH groups are facing inside the plane and its enantiomer where both the OH groups are projecting out of the plane.