Question

A survey investigated how many pounds heavier respondents were than their perceived ideal weight. Consider the following data
Gender Men West 15 13 19 13 Region Midwest South Northeast 20 19 18 16 20 15 24 19 17 20 13 18 Women
a. Determine if there is interaction between Region and Gender. Use the p-value approach and a significance level of 0.05 Fin
Choose the correct conclusion below. O A. Do not reject Ho. There is sufficient evidence that region and gender do interact O
Find the p-value p-value = (Round to three decimal places as needed) Choose the correct conclusion below. + A. Do not reject
Find the test statistic F=(Round to three decimal places as needed) Find the p-value p-value = (Round to three decimal places
0 0
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Answer #1

We have to perform 2 way ANOVA , we can use excel.

Go to Data menu ---> Data Analysis ----> Anova : Two-Factor With ReplicationFile Home Insert Page Layout Formulas Data Review View Sign in Sha IE Data Analysis ED Connections 21 22 E Properties At Sort

For Input range select Entire data table.

Rows per sample = 2 ( because there are 2 observation per sample )

A B D E H L 11 West с Mid west 20 South x Northeast 18 2 Men 15 19 - OK 3 13 20 15 1 Anova: Two-Factor With Replication Input

Click on OK..

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a)

A. H0 : Region and Gender do not interact to affect the mean response.

Ha : Region and Gender do interact to affect the mean response.

F = 0.265

P value = 0.849

As P value is greater than 0.05, we do not reject the null hypothesis H0.

C. Do not reject H0, There is insufficient evidence that region and gender do interact.

#b)

B. H0 : \mu _{A1} = \mu _{A2} = \mu _{A3} = \mu _{A4}

Ha : At least two regions have different averages in the discrepancy between existing and desired weight.

F = 1.916

P value = 0.206  

As P value is greater than 0.05, we do not reject the null hypothesis H0.

D. Do not reject H0 . There is insufficient evidence to indicate that at least two regions have different averages in the discrepancy between existing and desired weight.

#c)

C.H0 : \mu _{B1} = \mu _{B2}

Ha : There is a difference in averages in the discrepancy between existing and desired weight between the genders.

F = 0.316

P value = 0.589

As P value is greater than 0.05, we do not reject the null hypothesis H0.

D. Do not reject H0. There is insufficient evidence that there is a difference in averages in the discrepancy between existing and desired weight between the genders.

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