Homework Answers
using excel>data>data analysis>ANOVA with replication
we have
| Anova: Two-Factor With Replication | ||||||
| SUMMARY | west | midwest | south | northwest | Total | |
| Men | ||||||
| Count | 2 | 2 | 2 | 2 | 8 | |
| Sum | 28 | 36 | 39 | 33 | 136 | |
| Average | 14 | 18 | 19.5 | 16.5 | 17 | |
| Variance | 2 | 8 | 0.5 | 4.5 | 6.857143 | |
| Women | ||||||
| Count | 2 | 2 | 2 | 2 | 8 | |
| Sum | 32 | 41 | 38 | 32 | 143 | |
| Average | 16 | 20.5 | 19 | 16 | 17.875 | |
| Variance | 18 | 24.5 | 2 | 18 | 13.26786 | |
| Total | ||||||
| Count | 4 | 4 | 4 | 4 | ||
| Sum | 60 | 77 | 77 | 65 | ||
| Average | 15 | 19.25 | 19.25 | 16.25 | ||
| Variance | 8 | 12.91667 | 0.916667 | 7.583333 | ||
| ANOVA | ||||||
| Source of Variation | SS | df | MS | F | P-value | F crit |
| Gender | 3.0625 | 1 | 3.0625 | 0.316129 | 0.589346 | 5.317655 |
| Region | 55.6875 | 3 | 18.5625 | 1.916129 | 0.205502 | 4.066181 |
| Interaction | 7.6875 | 3 | 2.5625 | 0.264516 | 0.849176 | 4.066181 |
| Within | 77.5 | 8 | 9.6875 | |||
| Total | 143.9375 | 15 | ||||
Ans a ) option C is true
F = 0.265
p value = 0.849
Conclusion: option A is true
Ans b ) option B is true
F = 1.916
p value = 0.206
Conclusion: option D is true
Ans c ) option C is true
F =0.316
p value = 0.589
Conclusion:option B is true
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