Question

A compound shows an IR peak at 1740 cm-1. Its proton NMR spectrum consists of L.06 ppm, t, 6H2.03 ppm, quintet, 2H, 2.40 ppm,
0 0
Add a comment Improve this question Transcribed image text
Answer #1

Answer:

First question-

The NMR sprectra is for a total of 16 electrons. The only compound having a total of 16 electrons is the first compound- the diketone.

The assignment of peaks are shown below-

Second question-

F-C acylation can not be performed on aniline because the amino group forms a Lewis axid-base complex with the catalyst in which the aromatic ring is strongly deactivated.

Phenol also does not undergo F-C acylation due to the same reason.

Add a comment
Know the answer?
Add Answer to:
A compound shows an IR peak at 1740 cm-1. Its proton NMR spectrum consists of L.06...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • Question 18 (4 points) Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group...

    Question 18 (4 points) Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group gets acylated instead of the aromatic ring. The amino group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated. The amino group is strongly activating and multiple substitutions occur on the aromatic ring. The amino group is strongly deactivating preventing any substitution on the aromatic ring.

  • help asap Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group attacks the...

    help asap Friedel-Crafts acylation reactions cannot be performed on aniline because: The amino group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated. The amino group is strongly activating and multiple substitutions occur on the aromatic ring. The amino group is strongly deactivating preventing any substitution on the aromatic ring. The amino group gets acylated instead of the aromatic ring. Which of the following produces no reaction? -O'Na+ + H2O CH3 Li+...

  • What is the correct structure of cysteine at pH 137 The pKa values are 1.7 (carboxylic...

    What is the correct structure of cysteine at pH 137 The pKa values are 1.7 (carboxylic acid), 10.8 (amine (conjugate acid)), and 8.3 (sidechain, thiol). ΝΗ, * _dp OH ΝΗ, HS H2 -CÁCH NH2 CH es O Arrange the indicated protons by acidity, most acidic first: So ho į III IV OI>I> III > IV 01>II> III > IV 01> IV> III > II >I> IV > III Friedel-Crafts alkylation reactions cannot be performed on aniline because: The amino group...

  • Question 27 (4 points) A compound shows an IR peak at 1740 cm! Its proton NMR...

    Question 27 (4 points) A compound shows an IR peak at 1740 cm! Its proton NMR spectrum consists of 2.25 ppm, quintet, 2H, 2.36 ppm, t, 4H and 3.61 ppm, 5, 6H. The most likely structure is linio Question 28 (4 points) Which one of these compounds is insoluble in water, but soluble in HCl (aq)? anisole p-methylbenzoic acid aniline ethyl amine

  • Question 5 (4 points) What is the major product of the following reaction? 1. NaOET Eto...

    Question 5 (4 points) What is the major product of the following reaction? 1. NaOET Eto ΟΕΙ 2. Hot O OE EIO OH OE O O- EIO OH OEt OE EtO 애 OEt Question 6 (4 points) Friedel-Crafts acylation reactions cannot be performed on benzoic acid because: The carboxylic acid group gets acylated instead of the aromatic ring. The carboxylic acid group is moderately deactivating preventing any substitution on the aromatic ring. The carboxylic acid group attacks the Lewis acid...

  • Question 30 (4 points) Friedel-Crafts alkylation reactions cannot be performed on benzaldehyde because: The aldehyde group...

    Question 30 (4 points) Friedel-Crafts alkylation reactions cannot be performed on benzaldehyde because: The aldehyde group is strongly activating, and multiple substitutions occur on the aromatic ring. The aldehyde group gets alkylated instead of the aromatic ring. The aldehyde group attacks the Lewis acid to form an acid-base complex in which the aromatic ring is strongly deactivated The aldehyde group is moderately deactivating preventing any substitution on the aromatic ring. Question 31 (4 points) Which of the following produces no...

  • The IR/spectrum shows the value, 1st photo shows the instructions. Attached are 2 sets of spectra....

    The IR/spectrum shows the value, 1st photo shows the instructions. Attached are 2 sets of spectra. Each set is worth 25 points. Not all sets have a Mass Spectrum, but do have information that was obtained from MS and some sets do not have a "C-NMR and don't really need one. Look at each spectrum individually and clearly list and comment on the structural Characteristics you can determine from that spectrum. (Chemical shifts, splitting patterns, coupling constants, fragmentation patterns, absorption...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT