a)
ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
total sum | 94.00 | 674.60 | 128.40 | 1397.60 | 352.56 |
mean | 9.40 | 67.46 | SSxx | SSyy | SSxy |
Sample size, n = 10
here, x̅ = Σx / n= 9.400
ȳ = Σy/n = 67.460
SSxx = Σ(x-x̅)² = 128.4000
SSxy= Σ(x-x̅)(y-ȳ) = 352.6
estimated slope , ß1 = SSxy/SSxx =
352.56/128.4= 2.7458
intercept,ß0 = y̅-ß1* x̄ = 67.46- (2.7458
)*9.4= 41.6495
Regression line is, Ŷ= 41.6 +
( 2.75 )*x
b)
Predicted Y at X= 12 is
Ŷ= 41.64953 +
2.74579 *12= 74.6
-----------------------------
a)
ΣX | ΣY | Σ(x-x̅)² | Σ(y-ȳ)² | Σ(x-x̅)(y-ȳ) | |
total sum | 359.00 | 150.00 | 1938.83 | 137.76 | -22.20 |
mean | 59.83 | 25.00 | SSxx | SSyy | SSxy |
Sample size, n = 6
here, x̅ = Σx / n= 59.833
ȳ = Σy/n = 25.000
SSxx = Σ(x-x̅)² = 1938.8333
SSxy= Σ(x-x̅)(y-ȳ) = -22.2
estimated slope , ß1 = SSxy/SSxx =
-22.2/1938.8333= -0.0115
intercept,ß0 = y̅-ß1* x̄ = 25- (-0.0115
)*59.8333= 25.6851
Regression line is, Ŷ= 25.7 +
( -0.011 )*x
SSE= (SSxx * SSyy - SS²xy)/SSxx =
137.5058
std error ,Se = √(SSE/(n-2)) =
5.8631
correlation coefficient , r = SSxy/√(SSx.SSy)
= -0.043
b)
Regression line is, Ŷ= 25.6851 + ( -0.0115 )*x
c)
Predicted Y at X= 62 is
Ŷ= 25.68510 +
-0.01145 *62= 24.975
d)
x | y | (x-x̅)² | (y-ȳ)² | (x-x̅)(y-ȳ) | Ŷ | residual,ei=y-y^ |
62 | 20.5 | 4.6944 | 20.2500 | -9.750 | 24.98 | -4.4752 |
Please let me know in case of any doubt.
Thanks in advance!
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