Question

Question 13 < > 0/2 pts 53 99 Details Research was conducted on the amount of training for 5K and the time a contestant took to run the race. The researcher recorded the number of miles during training ( a 1 month period) and the time to complete the 5K. The results are below. Miles Trained 43 58 76 11 15 Time (Minutes) 24.5 20 30.9 16.4 37.7 33.2 a) Give the correlation coefficient. 44 b) Give the equation of the regression line. Round the values to 4 deimal places. This is in the form y = ax + b, so the slope goes in the first box and the y-inercept in the 2nd box. y = X + C) Predict the time in the 5K if someone trained 58 miles. Use the rounded values entered for the slope and intercept of the regression line to compute the predicted y-value. ya d) Give the residual for 58 miles trained. This is the actual y value for the runner who trained for miles minus the predicted value. Residual

Answer 1

Miles Trained) Time (minutes) χ2 ΑΑ 1936 2 Coo.2S 400 1ο18 8ο 24. S 8 49 20 43 S8 3ο.9 354.8ι 3344 1192-2 3ς 16. 4 168.96 124.4 S13, 33.4 121 14 21. 29 44. 4 1S 33. 2 498 125 11ο1. 14 244 A 341-55 142. 3 S889.3 13231 και 5 8 89.3 - 244 x 14 2.4 α) και: η Σκι - ΣκΣΗ Υ» Σ' - (Σχ'][»Σ' - (Σ) (612211 - 2003 ) (141455 - 162- 8 - ο. 38 22. 8 = αx +6 2 -0. 2606 Here η Σκη - Σκε η Σx? - (Σκ)? Gxs884 -3 - 244 x 16 2. 4 6 και 1324 - (24 42 6 - ΣΥΣ? Σx Σκι η Σχ. (Σκ)2 162- 4 x 13 24 - 244 xs889. 3 6 x 13 24 - (244) - 34.8446 :, και Π.Ε. 31. 8446 - 0.2002 3.8436 -0. 26ο6 και 3 - 94 x : s8 , -0. 26ο6 xs8 + 34. 84 36 22. 32 8 8 ei ι - 58) (d, residual at a=58 35g - ος 3 - 12. 288 - 3ο. 9 e, : -8. 1312