Consider the equilibrium below: If 1.4 mol of H2 and 1.4 mol of 12 was placed...
Consider the chemical reaction below at a given temperature and at equilibrium: H2(g) +12(g) = 2HI(g) Kc = 53.3 If 0.800 mol of H2 and 0.800 mol of 12 are placed in a 1.00L container and allowed to react, what is the [HI] when the reaction reaches equilibrium? [HIN In the expression for K N- (H2] [12]' The equilibrium concentrations can be expressed as follows: NOTE: This is NOT asking for the concentrations you solve for this is literally asking...
How many moles of H2 and HI will be present at equilibrium if 0.8430 mol HI are placed into a 1-L flask and allowed to react at a temperature where for the following reaction takes place: 2HI(g) H2(g) + I2(g) K = 16.5 mol H2? mol HI?
At a certain temperature, the equilibrium constant, ?c, for this reaction is 53.3. H2(g)+I2(g)↽−−⇀2HI(g)?c=53.3 At this temperature, 0.500 mol H2 and 0.500 mol I2 were placed in a 1.00 L container to react. What concentration of HI is present at equilibrium?
Calculate the concentrations of all substances present in the equilibrium mixture, if 2.35 mol of H2 and 2.35 mol of I2 are placed in a 10.0 L flask and allowed to come to equilibrium, at which time 3.76 mol of HI are present. The reaction is H2(g) + I2(g) --> 2HI (g) What is the value of Kc? What is the value of Kp?
Consider the following equilibrium with a Kc = 55.6 at a temperature of 698 K. H2(g) + I2(g) <--> 2HI(g) ΔH0 = + 26.5 kJ / mol If the initial concentrations were [H2] = 0.12 M; [I2] = 0.041 M; and [HI] = 2.6 M. Is the system at equilibrium, and if not, in which direction must it shift to establish equilibrium? Justify your answer. At the same 698 K, 0.50 mol of H2 and 0.88 mol of I2 are...
Given the equilibrium reaction: 2HI(g) H2(g) + I2(g) A sample mixture of HI, H2, and 12, at equilibrium, was found to have [H2]- 1.4 x 102 Mand [HI 4.0 x 102 M. If Keq 1.0 x 10, calculate the molar concentration of I2 in the equilibrium mixture, Enter your answer in the provided box. ]= м
show work please 3. Consider the following reaction where Kc 1.18 at 150K: 2HI(E)H2(g)+ 12(s) A reaction mixture was found to contain 0.0381 moles of HI, 0.0471 moles of H2, and 0.0364 moles of lz in a 1.00 L container. Is the reaction at equilibrium? And if not, what direction must it run in order to reach equiltibriurn? At equilibrium a 1.0-liter container was found to contain 0.20 mol of A, 0.20 mol of B, 0.40 mol of C, and...
An equilibrium mixture contains 0.950 mol HI, 0.490 mol I2, and 0.290 mol H2 in a 1.00-L flask. What is the equilibrium constant for the following reaction? 2HI(g) H2(g) + I2(g) K = How many moles of I2 must be removed in order to double the number of moles of H2 at equilibrium? mol I2
At a certain temperature, the equilibrium constant, Ke, for this reaction is 53.3. 2HI At this temperature, 0.400 mol of H2 and 0.400 mol of I2 were placed in a 1.00-L container to react. What concentration of Hl is present at equilibrium? Number
4.00 mols of H2 and 3 mols of I2 are placed in an evacuated 5.00L flask and then heated to 800K. The system is allowed to reach equilibrium. what will be the equilibrium concentration of each species? 2HI(g) <-----> H2(g) + I2(g) Kc= 0.016 @ 800k