Answer)
This question is a case of poisson distribution.
Mean rate for half an hour= 4 cars (Given)
According to poisson distribution-:
P(k events in an interval) = (e-*
k
)/k! where
is mean rate for that interval
Therefore, mean rate for an hour =
= 4*(mean rate for half an hour)= 8
Probability that atleast 3 cars will enter in an hour = P(x
3) = 1- P(x
2) = 1 - (P(0)+P(1)+P(2))
= 1 - e-8(1+8+82/2!) = 1 - e-8(1+8+32) = 0.9863
Hence, Probability that atleast 3 cars will enter in an hour = 0.9863
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