A sample of 2,000 individuals from a human population was scored for MN blood group.
The following genotypes were found:
Calculate the observed genotype frequencies and expected genotype frequencies under Hardy–Weinberg equilibrium to fill in the blanks to the following questions.
Remember to put a zero in front of the decimal point (e.g. 0.47) and round to the significant digits suggested.
The observed genotype frequencies (use to 3 significant digits) are:
MM =
MN =
NN =
The observed allele frequencies (use 4 significant digits) are:
M = p =
N = q =
The expected genotype frequencies (use 3 significant digits) under Hardy Weinberg Equilibrium are:
MM =
MN =
NN =
The frequency of heterozygotes in the observed population is than expected. (lower/higher)
Solution:
A population is said to be in Hardy-Weinberg equilibrium if the population is not evolving with respect to a certain gene, Hence the allelic and genotypic frequencies remain relatively constant over the cenrtain generations.
The allele and genotypic frequencies can be represented as follows:
= the frequency of the recessive allele
= the frequency of being heterozygous,
= the frequency of being homozygous recessive allele
Given data :
(i) The observed genotype frequencies
(ii) Calculating the allelic frequency :
First, determine the Expected frequency of the M allele (pp) and the N allele (qq):
(iii) The expected genotype frequencies from these allele frequencies:
Hope this helps
Happy learning!
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