Question

A particular fruit's weights are normally distributed, with a mean of 623 grams and a standard deviation of 36 grams. The heaviest 15% of fruits weigh more than how many grams? give answer in grams.

Answer 1

Answer---->>

"enlivo Pagod Colabor given that, grams and A particular forwitt weig We are normally distributed with a mean W = 623 Standord deviation 2 = 36 grams. consider, x= weights of a pesticular fruit x N / 4 = 623, 6= 36) consider PC X > a) = 6715 p (x <a) = 1-0:15 P(xca) = 0.85 2 2 from standerd hoes - P(22 9-6231 36 from standard normal distofbution table, p(241.049 =0.8508 1.2 PC250m=0.85 2 { Rounding to 'z' decimer from egno & egr ③ we get places } 0-623 36 a 623 + (36)(0.28) 653.67 The heaviest 15% of fruits weigh more than 653.6 grams