Question

derei derive elvation of maximum COP from the eluation of cop, & I To (THPTC) k - I²R e LI (THTc) + I²R and derive it for the mal conductivity to electrical resistance to

answer onlt if you know perfect otherwise leave for others

Answer 1

Given Equation is COP LITE - (TH-Tc) K - IR 2 dI (TH-Tc) + IR for getting max. Cop, the Condition is d(cop) dlc (a ICTA-TC) +1?e](QI+K) – [QIT -CTu-Tek- me]4dI) (LICTA -Te) + 1%e)? o ={{d}Ty -257, +39 -LITE +5°r)(25+23+ {[- Tok+Ix-xx}(x)}=0. => LITH -3% + &d + I kd + 2D THE _dick 2337 - LIPAK + + I IZRK + = 0 I3RL ditch 2 > 2² / TH + I²R2 + 1² kk 2 cancel I from the Equation IRd =O. 2²TH + + Rk > 2 THE - Tre + IRA 2 +RK) IRd + ZRK) 2 222 e TH - -R - (Id+2K) Condition for max. Cop, ad² substitute above value in 0,

(cop) = DIT - {( 1242k) - Te Jk - este 2 -R² (Id+2k) – TC Te} I²R + 247 If thermal Conductivity, k=o Electrical resistance, R=0; then and (COP) max. = DIT -o-telo- {o- o-te} 21 & I'R (cop) on Te (1+2I) M max -Te Id + I²R Te (1+21) (cop) = I(IR-LT)