Question

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An object is located 27cm from a thin symmetric lens, along the central axis the lens. P is greater than zero. The lateral magnification of the object provided by the lens is m = -0.25, and the index of refraction of the lens is 1.65. a) Determine the type of the lens . [1 Mark] b) Which side of the lens the image appears [1 mark] An object is located 23cm from a thin symmetric lens, along the central axis the lens. The lateral magnification of the object provided by the lens is m = -0.25, and the index of refraction of the lens is 1.65. c) Calculate the image distance q. ст [2 marks] d) Find the focal length of the lens. | ст [4 Marks]

Answer 1

Image formation -27cm AB-s object positive so conver lens is Power (P70) = -0.25 magnification Convex lens fve poweek is u. 27 cm) Image height object height v = 13.5cm -0.25 27 so If forms opposite Positive N is ③ side of object 23cm object located at n = 1.65 m =-0.25 -0.25*(-23) m al 23.com 4

112=1 (Air) for symmetric lens. ( -ý = my-na) [ ki Áz] But simplification purpose. from lens Makers formula. mi-o [ki ton] to R1 =-22 Symmetric = (nimi) २ R. ot We just need distance Image (m) =-0.25 u u=-23cm از ) ģ3 4 = 5.75cm q? $ -ty , U=-23cm f ㅗ २१ f 23 4 5 23 f = = 4.6cm 23 5 t from central q Axis