Question

these are the only questions i have left can someone help me with these questione please

An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 130 lb and 171 lb. The new population of pillots has normally duributed weights with a mean of 138 lb and a standard deviation of 25.1 lb. a. If a pilot is randomly selected, find the probability that his weight is between 130 b and 171 lb. The probability is approximately 0.4199)(Round to four decimal places as needed) ats 60 ources

Answer 1

mean It = 138 lb Given that Standard deviation =25.1 lb PC pilots wei leighing between 13016 and 171 lb) - P(130 2 X 2 171 Z Scorre for 13o16 = X-1 130-138 25-1 0.3187 Z score for 171 Ab E 171-138 1.314741 2 5 1 PC130 LX 2.171.) = PC -03187.22 ( 1.3147) 0.5307 The probability is approximately 0:5307 E = log.bpmi E Given that 2 bpm Ca 95040 30:95 The lowest value in the data set is a I bpm and the highest value 13 Range 10.9 - 41 = G2 The standard deviation is estimated as one forth of the range: os Range 1 4 4 Sample size n= 7 012 E where at 68 4 0² Za12 20:05 =

(1-36x17) = 277.5556 na 278 Hypothetical mean = $21.000 na 25 Sambile mean = $21562 Samjate Standard deviation $$ $ 1930 d=0:01 0.01 Null Bypothesis Ho y = $21000 Alternative hypothesis His 0# $21000 option is correct critical tyalue at Q=0:01 degree of freedom Colf)= n-1= 24 + 2.797 to = -2.797, 2:79.7 Rejection region Rejent null when test statistic is. beyond -2.9999 ts 2.797. test_statistic to I- siwn 21ooo 1.4561 hypothesis t = 215 62 1930 25 then calculated at value is less than critical value Fail to reject null hypothesis at 2=000]

There to not is not sufficient evidenée conclude that is to $21000 mean equal q n=184 proportion_ß = 84.2420:842 d=0:10 Hypothetical proportion = o do Null By pothesis Ho, p=0.80 Alternative Hypothesis Ha; Þ+ 0.80 option is correct test statistic e-Po Poli- po B Z n z = 0.842 0.8.0 0.8011=0.80) 184 23 1.4.2 critical Z value. cat 2 = 0.10 1.645 Since calculated alue is less? than eriti cal Nalue. then Fail to reject null at a=0.1o. null hypothesi