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An agricultural scientist decides to compare the effect three fertilizers have on the heights of a certain type of plant. For

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Answer #1

The Analysis of Variance Table is completed as follows:

Source of Variation Degrees of Freedom Sum of Squares Mean Square f P value
Treatments 2 210 210/2=105 105/3.429=30.624 0.0003
Error 7 24 24/7=3.429
Total 9 234

The entries in the Analysis of Variance Table are calculated as follows:

From the given data, the following Table is calculated:

Fertilizer A Fertilizer B Fertilizer C
n 3 3 4
Sum 84 54 72
Mean 28 18 18
\sum X^{2}_{ij} 2360 986 1298
Std. Dev. 2 2.646 0.816
SS 8 14 2

Xij = 84 +54 + 72 = 210

Σx? 2360 + 986 + 1298 = 4644 20

(ΣΧ;)? SStotal = Σx? 4644 2102 10 = 234 n

S Serror = 8 + 14 + 2 = 24

S Streatment 234 - 24 = 210

210 M Streatment 105 2

24 M Serror - 3.429 7

Test Statistic F is given by:

F = 105 3.429 30.624

By Technology,

P - Value = 0.0003

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