Solution:
A simple circuit is a walk that starts and ends with the same vertex and that does not contain any repeated edge or repeated vertex except the starting and the ending vertex.
Here,
is a simple circuit, because no vertex is repeated except the
starting and the ending vertex.
is not a simple circuit, because atleast one vertex
is repeated in between the starting and the ending vertex.
is not a simple circuit, because
is repeated in between the starting and the ending vertex.
In the graph shown below which walk is considered a simple circuit? tro 2 co es...
In the graph shown below which walk is considered a simple circuit? tro 2 co es 10 es US 26 There is no simple circuits. • V2 V₃ V4 V5 V2 V4 V2 V3 V4 V5 V2V4 VoVS V2 V3 V4V2 VIVO
QUESTION 18 In the graph shown below which walk is considered a simple circuit? e2 es VO 12 29 24 es C10 es e WA V4V2 V3 V4 V5 V2V4 Vo Vs V2 V3 V4V2 VIVO There is no simple circuits. V2 V3 V4 V5 V2
Question 1 (25 marks) Here below (Fig. 1) is the cross-sectional structure of an integrated circuit (IC) showing a metal- oxide-semiconductor field effect transistor (MOSFET). The four terminals of the MOSFET are connected to four voltages V1, V2, V3, and V4 respectively V V2 V: SO n+ n+ p-type Fig. 1 (a). What channel type is the MOSFET shown? (1 mark) (b). What are the common names of the four terminals connected to V1, V2, V3, and V4 respectively? Note...
21. In the circuit below Vi- V4 are unknown node voltages. Write and circle your node and supernode equations. ldentify (circle) any supernodes in the circuit. Write the dependent source equations (if any) that are necessary for the solution. ref node 40 Q 50 2 20 V V2 10 V 50lx 30 Q 20 Ω ww V3 V4 10 Q ww
21. In the circuit below Vi- V4 are unknown node voltages. Write and circle your node and supernode equations....
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For the circuit below, determine the MAGNITUDE of the
CURRENT passing through each resistor. V1 = 10 V,
V2 = 13 V, V3 = 14 V, R1 = 2 Ω,
R2 = 19 Ω, R3 = 9 Ω.
Please show all work.
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Practice [25%] The circuit shown left below is a waveform generation circuit, which consists of an integrator and a bistable multi-vibrator. The triangle symbol represents a unity-gain inverting amplifier such that V1 -v3 . R1-3k1, R2-2kQ, R3-1 ka, and C 0.1μF. The opamps are ideal except that they saturate at +10V and-10V. Be careful that the opamp in the bistable multi-vibrator is configured in a positive feedback way (a) On your answer book, sketch the output (v2) versus the input...
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