Question

The table below shows the percentage frequency distribution of income for undergraduate students. Left endpoint convention is used.

Income group (in euros) Percentage

0 - 500 41.07

500 - 1000 41.07

1000 - 1500 10.71

1500 - 2000 7.14

1.Calculate the median as a measure of location.

2 The arithmetic mean is an alternative measure of location. For the given data, which one of the two measures, the mean or the median, is a better summary measure for students’ income. Explain your answer

Answer 1

Date Solutions Given, mit point ) class O-500 500-1500 1000-1500 1500-2000 frequency. 41.07 4:07 10.H 7.14 c.f. 41.07 82.14 92.85 1 median = 1+13) xb where, 58 1/2 = 100/2 500-1000 is a median class. a= lower boundry of median class. cf. c.f of just before of median class. # frequency of median class: b = width of median class. ls soo of. = 41.07, f = 41.07. h=500 son 41:07 - median soot ootl 2) x 500 41.07 soot lof H68 608.7168

Date class soo-1000 freg.(A mid point (X) Xof. 41.07 2.50 10267.5 41.07 750 30802.s 10.H 1250 13387.5 7.14 175 12495.o 180o-isoo 150 - 200 mean = X - zf 66952.5 7 669.525. is The give data positively skewed (right skewed) Probably the best measure of location centre summary skewed distribution is median. median is value of centre of data. Here median is better summary measure students income. for