Answer.
Given .
Motion of the particle is given by
x =6t3 +2t m
Where x is distance and T is time.
If v is the velocity of the particle and a is the acceleration of the particle then
velocity is defined as rate of change of distance with respect to time.
i.e. v =dx / dt
or v = (d/dx) (6t3 +2t )
Or velocity of the particle is given by
v = 18t2 + 2 m/s
Acceleration of the particle is defined as rate of change of velocity.
I.e. a =dv/dt = (d/dt) ( 18t2 + 2)
or a = 36t m/s2
B.
A particle is moving with a motion defined by x = 6t3 + 2t m, what is the equation for the acceleration? A. a = 0 B. a = 36t m/s2 C. a = a = 3t5/10 + 3/3 m/s2 D. a = 18t? +2 m/s E. None of the above.
Please show all work and steps. Any help will be appreciated and thank you for your time! A particle is moving with a motion defined by x = 6t3 + 2t m, what is the equation for the acceleration? A. a = 0 B. a = 36t m/s2 C. a = 3t5/10 + t/3 m/s2 D. a = 18t2 +2 m/s E. None of the above.
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