A particle moving along the x axis has a position given by x=(24t-2t^3)m where t is...
A particle moving along the x axis has a position given by x=(24t-2t^3)m where t is measured in s. What is the magnitude of the acceleration of the particle at the instant when its velocity is zero?
Homework Answers
X(t) = 24t - 2t3
V(t) = dx/dt = 24-6t2 = 0 => t = 2
a(t) = dv/dt = -12t = -12*2 = -24 m/s2
magnitude of acceleration = 24 m/s2
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