Question

Rotational Dynamics Assignment (200 Points) • Due Friday, July 31 at 5:00 pm Equations are in a separate document entitled “Equations for Rotational Dynamics Assignment” • Moments of inertia formulas are provided on the last page of this document • Show all of your work when solving equations. It is not sufficient to merely have a correct numerical answer. You need to have used legitimate equations and algebra. You also need to have correctly used the data. • Units must be specified for any isolated number, not just your final answer • Force of gravity near Earth's surface = mg, where g = 9.80 m/s2 • Upload a scan of your handwritten answers to Canvas by clicking “Rotational Dynamics Assignment” in the Grades Menu option • Late submissions will immediately lose 40 points and an additional 40 points will be deducted each 24 hours that follow.
Please answer all of question 3

Answer 1

Given m 863 gm = 0.8 63 kg T 5.24 see. 98 um max height, H: 0.90 m min. hei height + b48 cm = 0.48 m (a). know, + T = m k K m I शा K = 1.24 0.863 5.24 21 ( 5

162 angular speed ATT T 5.24 1.2 Rekreth Rad/ fee (0), Amplitude, A = (98-40) cm 50 cm 0.5 m (d) Vimary Ꮗ Ꭿ 1:2 x 0.5 0.60 m/s. 느

(KE) max I m vnax 2 L x 0.863 x (0.6) 2 4 0./55 T- to (4) 5.24 f = 0.191 Hz