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A spring-mass-dashpot system with m=1, k= 2 and c= 2 (in their respective units) hangs in equilibrium. At time t=0, an extern

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Ang Given m=l, K=2, C = 2 i fcts = (71-IN we Know 9. cf motion is: myl tcytky =flt) (1) y + 2y + 2y = 17-t) y tayt2y = (22 => 20 + 4ct+2D + 2ct +2.00 +26 = -t Now compase both Side 26+2D = a 2C =0 > C=o 4C+2) = -1 E = 1/2+12 O+2) = -1 D-12 E = THy(t) = et (A cost + 8 Sint) + +(2-(4-1)) Now Know at t=0 ; y los O é ° (Acaso + B Sino) +447-60-1) I CA +o) ++ (+1) 2 A = I (

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