Question

Problem 2: The shaft has an outer diameter of 1.5 in. and a thickness of 0.125 in and is fixed at its ends A and B. The shaft is subjected to the couple (F = 251b). Determine the maximum shear stress in region AC and CB. F A 10 in. 6 in. F 8 in. 6 in. С B

Answer 1

Given dala Te TA Do = 1.5 in D = Do-2t = 1.5-2x0.125 = 1395 mm 1.2516 F=25ls 10 in sin * Те 166-676in Torque at point Ċ due to Force F becomes T= Force x Perpendicular distance T= 258 12 = 300 lb in. For series connection of shaft O AC & OBc 133.33 lb.in. Te. TALAC GJ TB. LBC G.J [ for same shaft GACJAC = Geilec TALAC = TB. LBC Tax 8 = TB 10 TB=0.8TA But TATTB = T TA+ 0.8TA = 300 TA = 166.67 lb in TB = 133.33 lb-in Sheor stress in region Ac and BC becomes TAC = 16TA IT D² (1-44) = 0.833 16x 166.67 = resi psi 1x1.5-3 (1-0-8334) KD; DO 485.05 TBC = 16 Te TIDO ()-K4) 16x 133.33 TT X1.53x (1)-0.8334) 388.02. PS ...Tac = 485.05 psi TBC = 388.02 psi