Question

5.- A steel arrow is made of two segments. Segment AC has a diameter of 0.5 "and CB has a diameter of 1". If the shaft is fixed at its ends A and B and subject to a torque of 500 Ib-ft. Find the maximum shear stress at arrow G_AB =10.8%  (10³) ksi.

Make the free body diagram and explain step by step.

0.5 in Fig. 5 (с D 500 lb-ft 5 in 1 in 8 in B 12 in

Answer 1

TA А osin 500 lb-ft T K Ic let sin B sin >k Izin G & J DAB Giuens t cow i tue lin cw :-ue :) Shear modules GAB es - Reaction Torques as follooss >> 6.1.T TA TBC fixeds PARO 2) Both sides are darba daca acot фор z) 0 =-TALAC TALCO TALB GxJAC GxJcb 10.8 xco3 ksi TAL To are calculated TA + TB = 500x 12 lbin TA TTB = 6000 lb-in bog 2 500 t G JOB Gooox 12 TA 8 L 5 J054 t f 74 Jau 2 4 32 32

E? TAC: 29.335 Ksi 2) TA = 720 &b in as TB = 5280 lb-in. z) shear stress in ARC : 16 TA Aci T da 16x 720 TAC 2) TACE 29335-439psi XX 0.53 2) T 16 Te W! shear stress in CD =) To Tider? 16x720 > To: 3666.9298 psi xxı3 z 3066 ksi 22 Tco Teo. 22 shear stress in DBZ TOB 164 TB I doo 22 T 16x 5280 DE =) ToB TX13 3.26890.819 psi E) TOB = 26.890 Rsi z Maximum Shear stress To masea Max { Tacito TOB} ż muse { 29.335, 3.66',26.89} 2) Tmara TAC = 29.335ksi