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A 304 stainless steel (yield strength 30 ksi) cylinder has an inner diameter of 4 in and a wall thickness of 0.1 in. If it is

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T-70 lb-ft solution : — Given data = vyt= 30 ksi dm = 4 m, t = p= 500 lb T = To tb-ft tout = din + 27 - 4+2(0:1) = 1.2 in Janstate of stress on the surface element A. Ox = 388.18 psiTay = 325.68 psi Acording to MSST . Taman TV ) ² + tay? = (39313) 27According DET US - ૧ જ’+ 3 - 3 38 -182 ( 3 25 (3) ઉ, = ૩૪ Psi > ૮૪૫-15 Posts majoria| ol|| 01 9| . = ૮84-માં

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