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Image for QUESTION 11 What is the role of PCl3 in the following reaction? It converts the carboxylic acid to an enoliz

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Answer #1

1)

in the given reaction

a ketone is reduced to alcohol

in general it can be done using NaBH4 or LiAlH4 in the presence of water

The H+ ion that attacks the 0xygen atom in the ketone is provided by H20 not by LiAlH4 or NaBH4

But

in the given reaction

A deuterium atom is attached to the Oxygen atom in the alcohol instead of H atom

so

a D+ should attack the OXygen atom in the ketone instead of H+ atom

so

it is provided by D30+ instead of H30+ and

in the presence of NaBH4 or LiAlH4

from the given options

the possible answer is


option D) 1. LiAlH4 2. D30+

2)

the reaction steps are given as

C6H5-Ch2- COOH + PCl3 ---> C6h5-Ch2-C0Cl


C6H5-CH2-C0Cl rearranges and forms enolate

C6H5-CH2-C0Cl = C6H5 - CH=C(Cl)OH


now this reacts with Br2


C6H5 - CH=C(Cl)OH + Br2 ---> C6H5 - CH(Br)-C0Cl + HBr


C6H5 - C(Br)-C0Cl + H20 ----> C6h5 - CH(Br) - COOH


so the correct answer for the role of PCl3 is

option A) It converts the carbolxylic acid to an enolizable acid chloride

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