Question

The torsional assembly in the Figure above consists of a cold-rolled stainless-steel tube AC with an outside diameter of 4 in., a wall thickness of 0.2 in., a shear modulus of G = 12,500 ksi, and an allowable shear stress of 35 ksi. The tube AC is connected to a solid cold-rolled brass segment CD at the flange C and has a diameter of 2.50 in., a shear modulus of G = 5,600 ksi, and an allowable shear stress of 20 ksi. The assembly is securely fastened to rigid supports at A and D. Determine the maximum permissible magnitude for the concentrated torque TB

50 in 32 in 20 in The torsional assembly in the Figure above consists of a cold-rolled stainless-steel tube AC with an outside diameter of 4 in., a wall thickness of 0.2 in., a shear modulus of G = 12,500 ksi, and an allowable shear stress of 35 ksi. The tube AC is connected to a solid cold-rolled brass segment CD at the flange C and has a diameter of 2.50 in., a shear modulus of G = 5,600 ksi, and an allowable shear stress of 20 ksi. The assembly is securely fastened to rigid supports at A and D. Determine the maximum permissible magnitude for the concentrated torque TB.

Answer 1

T, ? : 필 - 3.31 4 8.34 3 명 프 2.5" = 3.834 일 Tt Tt Ta=0.-@ | - T + Ta = o ㅋ) - T, - ⑥ | 얘it02 + 4, 20 O BO 22C 24 TS てみ - 0 C - - T from : T 도는 + 프는 - 1부(는) 이 또는 + L - : 다 J GC2 2 T TI C2 2 5 OCI - + 다 20 x 8, ky 3 32 12500X112) 5600X 닉 X 3.834 50 12500 x 42 s, 00128 + 0.004025 062 =- 2-6525{£ 35 26525 53 r since T까t2/ =13-19 ksi , 3o we Cowided ㄴ Tㅉ35Wi 그 -T3를 = 13-19×를X8613 = 18.54 fi<20%] L x 3.83 = 1 | T - TT - 33.43 - 1 51.25 pepin T = " - 13.11.8.42 57 TJ = -18-59 x 3.834 =-51.0 lipin (Time = TTE = 151-25-(57) = 208-25 Kipinn 의 2 뇌 kipin 2512