What is the ground state electron configuration of B?
1s22s2
1s2
1s22s22p2
1s22s22p1
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What is the ground state electron configuration of B? 1s22s2 1s2 1s22s22p2 1s22s22p1
What is the ground state electron configuration of Rubidium ( Rb ) ? a) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 c) 5s1 b) 1s2 2s2 2p6 3s2 3p6 4s2 4p6 4d10 5s1 d) 1s2 2s2 2p6 3s2 3p6 3d10 4p6 5s2 5p2
The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s22s2 2p6 352 3p1. It requires 8.298 eV to remove the outermost electron (2p1) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 ev. Since each electron is in a p orbital, the energy required will be equal to 8.298...
for a physical chemistry class . Consider the carbon atom (ground state configuration 1s22s22p2) and oxygen atom (ground state configuration 1s22s22p) (a) (8 points, 4 points each)) Write out the electron configuration (microstate) corresponding to the lowest energy configuration of carbon and oxygen. What are L and S in each case? (b) (6 points) What values of J are possible with the values of L and S that you found for carbon and oxygen in part (a)? Use Hund's third...
Given the ground state electron configuration of 16S 1s2 2s2 2p6 3s23p4, the distribution of the electrons on the last subshell 3p can be represented by Keep in mind the _ means an empty space in that mL Group of answer choices a. ↑↓ ↑↓ ↑↓ b. ↑↓ ↓_ ↑_ c. ↑↓ ↑_ ↑_ d. ↑↓ ↑↓ ↑_ __ __ e. ↑↓ ↑↓ __ Which of the following statements is FALSE ? Group of answer choices Like classical physics, we...
Question 22 5 pts The electronic configuration for boron is 1s22s22p1, and the electronic configuration for aluminum is 1s2 2s22p6 352 3p1. It requires 8.298 eV to remove the outermost electron (21) from boron. What can you say about the energy required to remove the outermost electron from aluminum (3p1)? Since each is the outermost electron around the atom, the energy required will be equal to 8.298 ev. Since each electron is in ap orbital, the energy required will be...
3. In the ground electronic state of Li atom, the electron configuration is 1s 2s'. If we neglect all the electron-electron repulsion, and assume all Li atomic orbitals follow those in hydrogenic atoms. Determine the energy (in eV) of the electron ground state: 1s2 2s1. Namely, the total energy of the 3 electrons in 1s 2s'. Check the end of chapter problem: E8C.2(a). 3. In the ground electronic state of Li atom, the electron configuration is 1s 2s1. If we...
8-076: Match Elements to Electron Configuration of Ions Match each element with the full ground-state electron configuration of the monatomic ion it is most likely to form. A 1s22s22p6 B 1s2 C 1s22s22p63s2 D 1s22s22p63s23p64s23d104p5 E 1s22s22p63s23p6 F 1s22s22p63s23p64s2 G 1s22s22p63s23p64s23d104p6 Mg Br Cl P F Ca
Ground state electron configuration Write the ground-state electron configurations for the following elements: B, V, Ni, As, I, Au.
What is the ground state electron configuration of Silver, (element 47, Ag)? What is the ground state electron configuration of Gold, (element 79, Au)? Why do these two metals have similar properties?
Part A Use the building-up principle to obtain the electron configuration of the ground state of iron. (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in complete form as 1s2 2s1 or in condensed form as [He]2s1.) Part B Iron is a Group 8B element in Period 4. What would you expect for the valence-shell configuration of iron? (Express your answer as a series of valence orbitals. For example, the valence-shell...