Question

Would the following solved for the currents in each series, the resistance is to be divided by 100, so on the first one for example the resistances are 5, 7.5, and 10, everything else is the same
11 R1 (500) A А A R2 (750 (2) E (10.0 V) 12 13 R3 (1000 (2) €2 (5.00 V)

Answer 1

Part-a3 را ہے۔ 2 A А 8,(10.00) R (500) V Iz ] R2(7580 & croorge & R3 (1000) Kirchhoff's law Applying Kirchoff's in loop O- lo- IR Iz Riz-5=0 in 2 B loop 10-I,R, I 3 R3 = 6 , Ri =52, R2= 7.502, R3=10ch > from equation ④ & (3 5- 51 - 7.51,-0 10-51 ŞI, 1013 20 - 5 +1063 -7.512=0 A 10 I3 = 7.5 Izts Putting this value in ean 10-51,-7.5 12 -5 20

5- SI -7.5 I 220 I, Izt Iz 5-55/2 513 -7,5 I 2 55, -5113,-1013 30 t 2 5 +2.5 I3=0 ² I 3-5 = 2 A U I 3 equation E from 10х3 7.5 Its 7,5 Iz Iz = 15 ñ 7.5 I g = 2A > from © > 5- Sii 7.5 A2 so 5 15 -51, = (-) I, = -2A ve sign shows that the direction current flow is considered direction. Opposide to the

Iz f E, C51001 R₂(8002) &z(10.04) Ş RESTO ITA Roche) A B/160) in loop 5+ I2 R2 + IIR, = 0 A o 5+ 8 I 2 + 10 II- in loop @ s to I 3R 3 t. I, R, 20 B ox in 15 6I3 t 10 I, loop ③ + IqR4 + I Ri 20 5 Te or С 5 + 5 I 4 + 10 I to It I4+2II or D L - Iz t It equation ④ uring It Is eqn ① ② © becomes 5+.8 I 2 + 10 I2 + 1014 - 1053 =) 5+ 1812+10 14 -10.13 =-) --- c

15 - 613 + 10 I2 7101q 1 o I 3=0 or 15 +1012 - 1653+1054 =0 F 4 or G It In + 2 Izt 214 - 2I3 =0 1+ 3 I 4 +212 2 I 3 = 0 & I 2-1653 +10 I4=0 + 10 I2 + 1554 -101350 F By ean is to d 5 t 10 - 613 -5 14 = 0 or 514 =10 10 -613 CA H from ean 57 18 Iz + 20-12I3-1053=0 25 +1812 -- 2213 = 0 H or 18 Iz = 22 I 3 -25

from сем G It 3 2 so 13 ) + 2/22-13-2) 18 Iz + 4 +13 It 25 cally 18 7 - 25 + 2212 Iz g أي 63-25 1oI3-162. I 3 4.5 T 38 در) 525 42 n 52I3 38 42 8 A I 3 = 3:41 A from egn SI4 10- 6x 3'41 5 I 4 - 10:46 I 4 2,092 negative sign shows sign shows that the direction of Iq is opposite to considered

direction from -> H 18 Iz E 22 X 3-41 25 al I = 2:78 A 12 A from I, + 3.41 = 2.98 2:09 I - 2.72 A direction is also opposite to the considered direction. a of I