Would like the solution of the current, divide the resistance by 100, so they are 10,8.6,5
Would like the solution of the current, divide the resistance by 100, so they are 10,8.6,5...
Would like the solution for current. resistance is divided by 100 so 5, 7.5, and 100 11 R1 (500) A А A R2 (750 (2) E (10.0 V) 12 13 R3 (1000 (2) €2 (5.00 V)
Would the following solved for the currents in each series, the resistance is to be divided by 100, so on the first one for example the resistances are 5, 7.5, and 10, everything else is the same 11 R1 (500) A А A R2 (750 (2) E (10.0 V) 12 13 R3 (1000 (2) €2 (5.00 V) EA (5.00 V) E2 (10.0 V) 12 Re (800 2) 1 R4 (500 ) N A A 위 A 13 A Ri (1000...
I don't understand how the answer for I1=7.99, I2=1.75, & I3=6.24 as theoretical current. Use the number provided in the data table not the diagram! Thank you 34 LABORATORY 3 4 Kirchhoff's Rules LABORATORY REPORT Data Table 1 Power Supply Voltages V 5.00 V & =_10.00 Calculations Table 1 Kirchhoffs rules for the circuit (1) KCR- (2) KVR1- (3) KVR2- E2 Theoretical Current (mA) % Error Experimental to Theoretical Current Resistor Values (9) Ri= 462 R2= 750 R3 = 1008...
The emfs in the figure below are &1 = 5.00 V and E2 = 18.0 V. The resistances are Ri = 15.5 12, R2 = 31.5 12, R3 = 47.5 12, and R4 = 59.0 12. Find the magnitude of the current in each resistor when the switch is in the following states. R2 R4 R E2 R3 A (a) open 11 = 12 = 13 14 = A A A A (b) closed 11 12 13 14 = =...
The emfs in the figure below are &z = 5.00 V and E2 = 21.0 V. The resistances are R1 = 18.0 , R2 = 32.00, R3 = 45.5 2, and R4 = 59.0 9. Find the magnitude of the current in each resistor when the switch is in the following states. R2 R4 R S R3 (a) open 11 = X Enter a number. differs significantly from the correct answer. Rework your solution from the beginning and check each...
Please help me solve for Calculations table 2 using the values in Data Table 2, not the diagram the set up is shown in figure34-4. Thank you 34 LABORATORY 3 4 Kirchhoff's Rules LABORATORY REPORT Data Table 1 Power Supply Voltages V 5.00 V & =_10.00 Calculations Table 1 Kirchhoffs rules for the circuit (1) KCR- (2) KVR1- (3) KVR2- E2 Theoretical Current (mA) % Error Experimental to Theoretical Current Resistor Values (9) Ri= 462 R2= 750 R3 = 1008...
The emfs in the figure below are e m f1 = 5.00 V and e m f2 = 18.0 V. The resistances are R1 = 17.0 Ω, R2 = 32.0 Ω, R3 = 48.0 Ω, and R4 = 59.0 Ω. Find the magnitude of the current in each resistor when the switch is in the following states. The emfs in the figure below are & = 5.00 V and E2 = 18.0 V. The resistances are R1 = 17.00, R2...
The emfs in the figure below are E1 = 5.00 V and E2 = 21.0 V. The resistances are R1 = 18.0 1, R2 = 32.0 N, R3 = 45.5 N, and R4 = 58.0 N. Find the magnitude of the current in each resistor when the switch is in the following states. R2 R4 S R3 A (a) open 11 = 12 = 13 = 14 = A A A А (b) closed 11 = 12 = 13 =...
Compute the equivalent resistance of the network in the figure below, and find the current in each resistor. (R1 = 4.00 Ω, R2 = 7.00 Ω, R3 = 10.0 Ω, R4 = 2.00 Ω, and ε = 61.0 V.) The battery has negligible internal resistance. equivalent resistance Incorrect: Your answer is incorrect. Ω current in each resistor Incorrect: Your answer is incorrect. A (Resistor R1) A (Resistor R2) A (Resistor R3) A (Resistor R4)
Find the equivalent resistance of the circuit below. R1=333 12, R2=100 N2, R3=1000 N2, R4=1.750 kN2, R5=550 N2, R6=3.5 k 2. (Report result to nearest whole number) R1 w R2 V R3 w R4 w R5 R6