Question

The flow at a wastewater treatment plant is 2 MGD. The chlorine contact basin is 5 feet wide and 5 feet deep. To have a 90-minute contact time, how long is the basin? 668 ft 268 ft 153 ft 450 ft

Answer 1

* -solution -Y Criven 0 volumetric flow rate (CP) = 9 million gallone day I million (lons E 105 gallone 1 gallons day E 1440 min so convert million gallon lloneldag to go gallons / min ņ 2 million gallone Idung 2 xio@gallons so > 1440min 2 million gullone I day = 1388.89 galloni min $0 volumetric floue rande = 1388.89 gallons Imitar vi cuidth g basin = 5ft basin = 5ft Assume height of Lenth og begin = reft

* 80 volume basin calculated as a Volume lenth x width & height => yolume = de 2cft x 5 ff x 564 => volume = 25x« f43 Since 1 f+3 = 7.481 gallons 25x98 +3 = 95*** 7.481 gallons volume 525XXX 7.481 gullong Til contact time = 90 min * case- anfeect time calculated CLS confect time volume of basin volumetric flow rate

since confect-time = go min volumetric flove rare =-25 = 1388.89 gallons Imin yolume Bagin = 95xx7.481 gallone of but în above, equation go mine 25*** 7.481 gallone 1388.89 gallone / min > gomjú x 13 88: 89 gallong min = 95x2x7.481 galyong > 95xxx 7.481 gox1388.89 ) x = 90 x 1388.89 25x3.481 > 2 668.36 ft x 668 ft Anews Ane cler -> Lenth (F) = 668 ft first part is correct option