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A 12-Et simply supported beam is having a uniformly distributed load of...
Chapter 15, Supplemental Question 121 The simply supported beam supports a uniformly distributed load of w-300...
Chapter 15, Supplemental Question 121 The simply supported beam supports a uniformly distributed load of w-300 lb/ft between supports A and B and a concentrated load of P = 2165 lb at end C. The cross-sectional dimensions of the beam shown in the second figure are b 12 in., t2.50 in.,d-11 in., and tw-2.50 in. Using L-14 ft and xK3 ft, determine the principal stresses and the maximum shear stress acting at point K, which is located at a distance...
2. A 30 ft long simply supported beam supports a uniformly distributed load of 2 kips/ft...
2. A 30 ft long simply supported beam supports a uniformly distributed load of 2 kips/ft over the entire span. The beam and cross section are shown below. Draw the shear and moment diagrams, find the neutral axis location, moment of inertia of the composite section, the maximum bending stress on the cross section. (40 points) 10" 2 k/ft 1-3" 30'-0"
The simply supported beam, with a U cross section, is subjected to a uniformly distributed force...
The simply supported beam, with a U cross section, is subjected to a uniformly distributed force of 8 kN/m and a concentrated load of 12 kN as shown. (a) Determine the reaction at supports A and B, (b) sketch the shear diagram and the moment diagram, (c) determine the location of the neutral axis of the cross section and calculate its area moment of inertia about the neutral axis, and (d) determine absolute maximum bending stress and (e) absolute maximum...
16.6a) A simply supported beam is to span 15 ft. It will support a uniformly distributed load of ...
16.6a) A simply supported beam is to span 15 ft. It will support a uniformly distributed load of 2 kips/ft over the full span and a concentrated load of 60 kips at mid-span. What is the required plastic section modulus Zx? (Include self-weight) 16.6b) A simply supported beam is to span 15 ft. It will support a uniformly distributed load of 2 kips/ft over the full span and a concentrated load of 60 kips at mid-span. Deflection is not to...
P9.007 (GO Tutorial) A 6.8 m long simply supported wood beam carries a uniformly distributed load...
P9.007 (GO Tutorial) A 6.8 m long simply supported wood beam carries a uniformly distributed load of 10.6 kN/m, as shown in Figure A. The cross-sectional dimensions of the beam as shown in Figure B are b = 180 mm, d-460 mm, ун-92 mm, and VK-1 44 mm. Section a-a is located at x-1.3 m from B (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-a, determine the...
A5.2 m long simply supported wood beam carries a uniformly distributed load of 12.9 kN/m, as...
A5.2 m long simply supported wood beam carries a uniformly distributed load of 12.9 kN/m, as shown in Figure A. The cross-sectional dimensions of the beam as shown in Figure Bare b = 195 mm, d = 485 mm. yy = 81 mm, and yx = 167 mm. Section 3-a is located at x = 1.4 m from B. (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-3,...
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip ...
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect the lightest rectangular wood beam that can safely support the loads (neglect the weight of the beam). The allowable stress in bending is 1200 psi and in shear parallel to the grain 100 psi
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect...
A simply supported wood beam with a span of L = 12 ft supports a uniformly...
A simply supported wood beam with a span of L = 12 ft supports a uniformly distributed load of w0 = 300 lb/ft. The allowable bending stress of the wood is 1.70 ksi. If the aspect ratio of the solid rectangular wood beam is specified as h/b = 3.00, calculate the minimum width b that can be used for the beam.
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal ...
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal to 6.0 kips/t. Beam properties are as follows: b-14 in, d-24 in, 4,000 psi (normal-weight concrete) and fy -60,000 psi. Design shear reinforcement for the entire beam (you can use symmetry if applicable). Use two different spacings over the beam length to come up with economical design. Perform all necessary checks and calculations. Draw final design for shear ma reinforcement indicating distribution (i.e, lengths,...
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed...
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed load over its entire 1.2m length. Specify the maximum allowable load if the beam is made from malleable iron, ASTM A220, class 80002. The allowable tensile stress is 164 MPa and allowable compressive stress is 412 MPa. The centroid of the section is located at 35 mm from the bottom and moment of inertia are Ix = 2.66 x 10 mm". (a) Draw loading...
Chapter 15, Supplemental Question 121 The simply supported beam supports a uniformly distributed load of w-300 lb/ft between supports A and B and a concentrated load of P = 2165 lb at end C. The cross-sectional dimensions of the beam shown in the second figure are b 12 in., t2.50 in.,d-11 in., and tw-2.50 in. Using L-14 ft and xK3 ft, determine the principal stresses and the maximum shear stress acting at point K, which is located at a distance...
2. A 30 ft long simply supported beam supports a uniformly distributed load of 2 kips/ft over the entire span. The beam and cross section are shown below. Draw the shear and moment diagrams, find the neutral axis location, moment of inertia of the composite section, the maximum bending stress on the cross section. (40 points) 10" 2 k/ft 1-3" 30'-0"
P9.007 (GO Tutorial) A 6.8 m long simply supported wood beam carries a uniformly distributed load of 10.6 kN/m, as shown in Figure A. The cross-sectional dimensions of the beam as shown in Figure B are b = 180 mm, d-460 mm, ун-92 mm, and VK-1 44 mm. Section a-a is located at x-1.3 m from B (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-a, determine the...
A5.2 m long simply supported wood beam carries a uniformly distributed load of 12.9 kN/m, as shown in Figure A. The cross-sectional dimensions of the beam as shown in Figure Bare b = 195 mm, d = 485 mm. yy = 81 mm, and yx = 167 mm. Section 3-a is located at x = 1.4 m from B. (a) At section a-a, determine the magnitude of the shear stress in the beam at point H. (b) At section a-3,...
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect the lightest rectangular wood beam that can safely support the loads (neglect the weight of the beam). The allowable stress in bending is 1200 psi and in shear parallel to the grain 100 psi
14.54 A simply supported rectangular beam with a span of 6 ft has a concentrated load of 4.1 kip at midspan. Se- lect...
A 26.0 ft. simply supported beam is subjected to factored uniformly distributed load of wa equal to 6.0 kips/t. Beam properties are as follows: b-14 in, d-24 in, 4,000 psi (normal-weight concrete) and fy -60,000 psi. Design shear reinforcement for the entire beam (you can use symmetry if applicable). Use two different spacings over the beam length to come up with economical design. Perform all necessary checks and calculations. Draw final design for shear ma reinforcement indicating distribution (i.e, lengths,...
The simply-supported beam having I-beam cross-section as shown in figure is to carry a uniformly distributed load over its entire 1.2m length. Specify the maximum allowable load if the beam is made from malleable iron, ASTM A220, class 80002. The allowable tensile stress is 164 MPa and allowable compressive stress is 412 MPa. The centroid of the section is located at 35 mm from the bottom and moment of inertia are Ix = 2.66 x 10 mm". (a) Draw loading...
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