Question

Instruction for Hypothesis Testing (Problems 17-25, Except 24) For One Population: Show your work for finding Test value, Critical value(s), or P-value. For Two Populations: Use your calculator to give the values of Test Value and P-value. O O O O Indicate your parameter Indicate the claim List the given information Then start your five steps. Pay attention to the method, such as Traditional or P- value Put the step numbers inside a box For step (1): Indicate Ho Indicate Hi Tell if Ho or Hy is the claim (put the word claim inside parentheses in front of the claim sentence) o Identify the type of test such as right-tail test, left-tail test, or two-tail test The name of the test is in the direction of H1 For step (2): Find Critical Value (CV) for Traditional method Find Test value for P-value method For step (3): Find Test value for Traditional method Find P-value for P-value method For step (4), decide to reject Ho or not reject Ho. Circle your result. For Traditional method, draw the bell curve. Separate critical region from non-critical region using CV and locate your test value on the graph For P-value method, compare your P-value with a. For step (5), write your summary according to the slide #5 of lesson 8.2. Other similar statements are not expectable! On this step: Underline is or is not, also underline reject or support. . O O . O O . o O o

Answer 1

22.

Given that,
sample 1
s1^2=17029.336, n1 =7
sample 2
s2^2 =5360.494, n2 =8
null, Ho: σ^2 = σ^2
alternate, H1: σ^2 != σ^2
level of significance, α = 0.1
from standard normal table, two tailed f α/2 =3.866
since our test is two-tailed
reject Ho, if F o < -3.866 OR if F o > 3.866
we use test statistic fo = s1^1/ s2^2 =17029.336/5360.494 = 3.177
| fo | =3.177
critical value
the value of |f α| at los 0.1 with d.f f(n1-1,n2-1)=f(6,7) is 3.866
we got |fo| =3.177 & | f α | =3.866
make decision
hence value of |fo | < | f α | and here we do not reject Ho
ANSWERS
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null, Ho: σ^2 = σ^2
alternate, H1: σ^2 != σ^2
test statistic: 3.177
critical value: -3.866 , 3.866
decision: do not reject Ho
p value is 0.078
we do not have enough evidence to support the claim that the variance of heights of tall buildings in Denver is equal to the variance of heights of tall
buildings in Detroit.