Question

Instruction for Hypothesis Testing (Problems 17-25, Except 24) For One Population: Show your work for finding Test value, Critical value(s), or P-value. For Two Populations: Use your calculator to give the values of Test Value and P-value. O O O O Indicate your parameter Indicate the claim List the given information Then start your five steps. Pay attention to the method, such as Traditional or P- value Put the step numbers inside a box For step (1): Indicate Ho Indicate Hi Tell if Ho or Hy is the claim (put the word claim inside parentheses in front of the claim sentence) o Identify the type of test such as right-tail test, left-tail test, or two-tail test The name of the test is in the direction of H1 For step (2): Find Critical Value (CV) for Traditional method Find Test value for P-value method For step (3): Find Test value for Traditional method Find P-value for P-value method For step (4), decide to reject Ho or not reject Ho. Circle your result. For Traditional method, draw the bell curve. Separate critical region from non-critical region using CV and locate your test value on the graph For P-value method, compare your P-value with a. For step (5), write your summary according to the slide #5 of lesson 8.2. Other similar statements are not expectable! On this step: Underline is or is not, also underline reject or support. . O O . O O . o O o

Answer 1

Ans 22 ) using excel>addin>phstat>two sample tets

we have

F Test for Differences in Two Variances
Data
Level of Significance	0.05
Larger-Variance Sample
Sample Size	7
Sample Variance	17029.33333
Smaller-Variance Sample
Sample Size	8
Sample Variance	5360.5
Intermediate Calculations
F Test Statistic	3.1768
Population 1 Sample Degrees of Freedom	6
Population 2 Sample Degrees of Freedom	7
Two-Tail Test
Upper Critical Value	5.1186
p-Value	0.1561
Do not reject the null hypothesis

the null and alternative hypothesis is

Ho:$\sigma_1^2=\sigma_2^2$

Ha:$\sigma_1^2\neq \sigma_2^2$

the variance of denver (s₁²) =17029.333

the variance of denver (s₂²) =5360.5

F =

F = 17029.33/5360.5

F = 3.1768

p value =0.1561

Since p value is greater than 0.05 so we reject Ho and conclude that variance are not equal