Question

Suppose that two people standing 2 miles apart both see the burst from a freworks display, Aher a period of time, the first person standing at point Ahears the burst. Four seconds later, the second person standing at point hears the burst. If the person at point is dus west of the person at point and if the display is known to occur due north of the person at point where did the freworks display occur? Note that sound travela el 1100 feet per second The fireworks display is feet north of the person at point A (Do not round until the final answer. Then found to the nearest foot as needed)

Answer 1

Solutions Given that : A and B are standing 2 miles apart, fire work display E E ne fra y S B А zmiles 2120 ft in Let A hear sound = t seconds speed of sound = 1100 1100 ftis X= too ft y = 1180 (.t+3) ft y²- x² = (211203² 1100 (t+3j2-12 - 21120 √9+6t 21120 1100 t= 59.94S Hence x = 59.9ux 1100 = 65934 ft. Therefore, The fire work display is 65934. ft north of the person at point A.

Solution Ellipse Center 10,0) b=5 Vertex = (0,7) Equation quellipse -1 22 62 at center (oo) 2 Vertex = (h, K-Q) = (0,7) Co,-a) = (0,7) Q=-1 b=5 Therefore, equation of ellipse x² yz =1 52 ge² y² + 25 49 of $ 5 х li y'
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