Question

If we know that the length of time it takes a university student to find a parking space in the university car park follows a normal distribution with a mean of 4.5 minutes and a standard deviation of 1 minute, find the probability that a randomly selected university student will find a parking space in the car park in less than 3 minutes.

Show your working or attach an image of your handwritten solution (write your name at the top of your paper)

Answer 1

Solution :

Given that ,

P(x < 3)

= P[(x - $\mu$ ) / $\sigma$ < (3 - 4.5) / 1]

= P(z < -1.50)

Using z table,

= 0.0668